0=2w^2+11w-350

Solution for 0=2w^2+11w-350 equation:

0=2w^2+11w-350

We move all terms to the left:

0-(2w^2+11w-350)=0

We add all the numbers together, and all the variables

-(2w^2+11w-350)=0

We get rid of parentheses

-2w^2-11w+350=0

a = -2; b = -11; c = +350;
Δ = b2-4ac
Δ = -112-4·(-2)·350
Δ = 2921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{2921}}{2*-2}=\frac{11-\sqrt{2921}}{-4}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{2921}}{2*-2}=\frac{11+\sqrt{2921}}{-4}
$